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LeetCode
LeetCode
  • Introduction
  • Problems
    • Algorithms
      • Easy
        • 844. Backspace String Compare
        • 905. Sort Array By Parity
    • Database
      • Easy
        • #175 Combine Two Tables
        • #181 Employees Earning More Than Their Managers
        • #182 Duplicate Emails
        • #183 Customers Who Never Order
        • #196 Delete Duplicate Emails
        • #197 Rising Temperature
        • #511 Game Play Analysis I
        • #584 Find Customer Referee
        • #586 Customer Placing the Largest Number of Orders
        • #595 Big Countries
        • #596 Classes More Than 5 Students
        • #607 Sales Person
        • #620 Not Boring Movies
        • #627 Swap Salary
        • #1050 Actors and Directors Who Cooperated At Least Three Times
        • #1084 Sales Analysis III
        • #1141 User Activity for the Past 30 Days I
        • #1148 Article Views I
        • #1179 Reformat Department Table
        • #1407 Top Travellers
        • #1484 Group Sold Products By The Date
        • #1527 Patients With a Condition
        • #1581 Customer Who Visited but Did Not Make Any Transactions
        • #1587 Bank Account Summary II
        • #1667 Fix Names in a Table
        • #1693 Daily Leads and Partners
        • #1729 Find Followers Count
        • #1741 Find Total Time Spent by Each Employee
        • #1757 Recyclable and Low Fat Products
        • #1795 Rearrange Products Table
        • #1873 Calculate Special Bonus
        • #1890 The Latest Login in 2020
        • #1965 Employees With Missing Information
      • Medium
        • #176 Second Highest Salary
        • #177 Nth Highest Salary
    • Shell
      • Easy
        • #193 Valid Phone Numbers
        • #195 Tenth Line
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  1. Problems
  2. Database
  3. Easy

#1729 Find Followers Count

Previous#1693 Daily Leads and PartnersNext#1741 Find Total Time Spent by Each Employee

Last updated 3 years ago

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SELECT user_id, COUNT(*) AS followers_count
FROM Followers
GROUP BY user_id
https://leetcode.com/problems/find-followers-count/